-5p^2-18p-9=0

Solution for -5p^2-18p-9=0 equation:

-5p^2-18p-9=0

a = -5; b = -18; c = -9;
Δ = b2-4ac
Δ = -182-4·(-5)·(-9)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-12}{2*-5}=\frac{6}{-10}
=-3/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+12}{2*-5}=\frac{30}{-10}
=-3
$